X^2+50x-240=0

Solution for X^2+50x-240=0 equation:

X^2+50X-240=0

a = 1; b = 50; c = -240;
Δ = b2-4ac
Δ = 502-4·1·(-240)
Δ = 3460
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3460}=\sqrt{4*865}=\sqrt{4}*\sqrt{865}=2\sqrt{865}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-2\sqrt{865}}{2*1}=\frac{-50-2\sqrt{865}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+2\sqrt{865}}{2*1}=\frac{-50+2\sqrt{865}}{2}
$